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python编写扎金花小程序的实例代码

时间:2021-02-23|栏目:Python|点击:

游戏规则:

一付扑克牌,去掉大小王,每个玩家发3张牌,最后比大小,看谁赢。

有以下几种牌:

豹子:三张一样的牌,如3张6.

顺金:又称同花顺,即3张同样花色的顺子, 如红桃 5、6、7

顺子:又称拖拉机,花色不同,但是顺子,如红桃5、方片6、黑桃7,组成的顺子

对子:2张牌一样

单张:单张最大的是A

这几种牌的大小顺序为, 豹子>顺金>顺子>对子>单张

程序需要实现的点:

  1. 先生成一付完整的扑克牌
  2. 给5个玩家随机发牌
  3. 统一开牌,比大小,输出赢家是谁

主要思路:

 把各种牌用积分来计算,最后加上三张牌的基础积分。即:最终积分=基础积分+牌型积分。最后比较最红积分,谁的积分大,谁排名就靠前。 附上源码:

# -*- coding: utf-8 -*-
"""
# @Time   : 2021-01-07 14:55
# @author  : jianwei
# @Software : PyCharm
"""

import random
import operator

puke = [] # 存储扑克牌
num_list = ['2', '3', '4', '5', '6', '7', '8', '9', '10', 'J', 'Q', 'K', 'A']
hua_list = ['梅花', '红桃', '黑桃', '方块']
sotr_dic = {'2': 0, '3': 1, '4': 2, '5': 3, '6': 4, '7': 5, '8': 6, '9': 7, '10': 8, 'J': 9, 'Q': 10, 'K': 11, 'A': 12,
      '对子': 15, '顺子': 30, '顺金': 60, '豹子': 100}
count_new_list = [] # 存储玩家分数和排序后排名
count_dic = {} # 存储玩家分数
# 准备52张扑克
for hua in hua_list:
  for num in num_list:
    a = hua + num
    puke.append(a)
player_dic = {'玩家1': [], '玩家2': [], '玩家3': [], '玩家4': [], '玩家5': []}
# 随机给五个玩家发牌
# print(len(puke))
for key, value in player_dic.items():
  for i in range(3):
    plate = random.sample(puke, 3)
    player_dic[key] = plate
    for i in plate:
      puke.remove(i)


# print(player_dic)

# 获取玩家的牌型
def paixing(list1):
  num = []
  huase = []
  for i in list1:
    a = i[2:]
    b = i[:2]
    num.append(a)
    huase.append(b)
  return num, huase


# 对数字的牌型进行排序
def sotr(num):
  new_num = []
  sort_list2 = []
  list1 = []
  for i in num:
    new_num.append(sotr_dic[i])
  new_num = sorted(new_num)
  for new in new_num:
    sort_list2.append([k for k, v in sotr_dic.items() if v == new])
  for m in sort_list2:
    for n in m:
      list1.append(n)
  return list1


# 对玩家的牌形统计分数
def count(num, huase):
  a = 0
  base_count = sotr_dic[num[0]] + sotr_dic[num[1]] + sotr_dic[num[2]]
  if num[0] == num[1] and num[1] == num[2]:
    paixing = '豹子'
    a = base_count + sotr_dic[paixing]
    # print(paixing, a)
  elif (sotr_dic[num[0]] + 1 == sotr_dic[num[1]] and sotr_dic[num[2]] - 1 == sotr_dic[num[1]]) and (huase[0] == huase[
    1] and huase[1] == huase[2]):
    paixing = '顺金'
    a = base_count + sotr_dic[paixing]
    # print(paixing, a)
  elif (sotr_dic[num[0]] + 1 == sotr_dic[num[1]]) and (sotr_dic[num[2]] - 1 == sotr_dic[num[1]]) and (
      huase[0] != huase[
    1] or huase[1] != huase[2]):
    paixing = '顺子'
    a = base_count + sotr_dic[paixing]
    # print(paixing, a)
  elif (num[0] == num[1] and num[1] != num[2]) or (num[1] == num[2] and num[0] != num[1]) or (
      num[0] == num[2] and num[1] != num[0]):
    paixing = '对子'
    a = base_count + sotr_dic[paixing]
    # print(paixing, a)
  else:
    a = base_count
  return a


# 对存储玩家分数的字典进行排序
def compare(count_dic):
  d = list(zip(count_dic.values(), count_dic.keys()))
  return sorted(d, reverse=True)


for key, value in player_dic.items():
  # print(key,value)
  num, huase = paixing(value)
  # print(num,huase)
  num = sotr(num)
  # print(num, huase)
  count1 = count(num, huase)
  # print(count1)
  count_dic[key] = count1
  print(key + "的牌为:" + str(value))
  count_new_list = compare(count_dic)
# print(count_new_list)
print('最终排名:' + "\t" + count_new_list[0][1] + "第一名" + "\t" + count_new_list[1][1] + "第二名" + "\t" + count_new_list[2][
  1] + "第三名" + "\t" + count_new_list[3][1] + "第四名" + "\t" + count_new_list[4][1] + "第五名")

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